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A cyclist speeds up from 3 m/s to 7 m/s in 8 seconds.

What is its change in velocity?

What's its acceleration?

Sagot :

Answer:

Change in velocity = 4 m/s and acceleration = 0.5 m/s²

Explanation:

Given that,

Initial velocity, u = 3 m/s

Final velocity, v = 7 m/s

Time, t = 8 seconds

(a) The change in velocity of a cyclist.

[tex]\Delta v=v-u\\\\=7\ m/s-3\ m/s\\\\=4\ m/s[/tex]

(b) Acceleration,

[tex]a=\dfrac{\Delta v}{t}\\\\a=\dfrac{4\ m/s}{8\ s}\\\\a=0.5\ m/s^2[/tex]

So, the change in velocity is 4 m/s and acceleration is 0.5 m/s².

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