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Sagot :
Answer:
[tex]P(R\ and\ B) = 0.0256[/tex]
Step-by-step explanation:
Given
[tex]Red = 22[/tex]
[tex]Yellow = 38[/tex]
[tex]Green = 20[/tex]
[tex]Purple = 28[/tex]
[tex]Blue = 26[/tex]
[tex]Orange = 16[/tex]
Required
Determine the probability of red then blue jelly? i.e. P(R and B)
From the question, we understand that the red jelly bean was not replaced. This means that the number of jelly beans reduced by 1 after the picking of the red jelly bean
So, we have:
[tex]P(R\ and\ B) = P(R)\ and\ P(B)[/tex]
This is then solved further as:
[tex]P(R\ and\ B) = P(R)\ *\ P(B)[/tex]
[tex]P(R\ and\ B) = \frac{n(R)}{Total}\ *\frac{n(B)}{Total - 1}[/tex]
The probability has a denominator of Total - 1 because the number of jelly beans reduced by 1 after the picking of the red jelly bean
The equation becomes:
[tex]P(R\ and\ B) = \frac{22}{150}\ *\frac{26}{150- 1}[/tex]
[tex]P(R\ and\ B) = \frac{22}{150}\ *\frac{26}{149}[/tex]
[tex]P(R\ and\ B) = \frac{22*26}{150*149}[/tex]
[tex]P(R\ and\ B) = \frac{572}{22350}[/tex]
[tex]P(R\ and\ B) = 0.02559284116[/tex]
[tex]P(R\ and\ B) = 0.0256[/tex]
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