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Sagot :
Part A: 5,333[tex]\frac{1}{3}[/tex] square yards
EX: The length of the football field is 100 yards. The width of the field is 53[tex]\frac{1}{3}[/tex] yards.
Part B: 1/10 inch per yard
EX: The scale used in the drawing is 1 inch to 10 yards. I can represent this ratio in several different ways: 1 inch to 10 yards, 1 inch : 10 yards, 1 in/ 10 yd or 1/10
Part C: 10 inches
EX: Set up a proportion where the numerators are the measurements in the scale drawing and the denominators are the actual measurements of the football field:
1 in. / 10 yd. = × in. / 100 yd.
Cross multiply, and then divide both sides by 10 to solve for x:
100 = 10x
10 = x
Part D: 5 1/3
EX: Use the actual width of 53[tex]\frac{1}{3}[/tex] yards and the scale to find the width of the field in the scale drawing.
Set up a proportion where the numerators are the measurements in the scale drawing and the denominators are the actual measurements of the football field:
1 in / 10 yd = 53[tex]\frac{1}{3}[/tex] yd
Cross multiply, and then divide both sides by 10 to solve for x:
10x = 53[tex]\frac{1}{3}[/tex]
x = 160/3 ÷ 10
x = 16/3
x = 5[tex]\frac{1}{3}[/tex]
Part E: 53 1/3
EX: In the scale drawing, the length of the football field is 10 inches and the width is 5[tex]\frac{1}{3}[/tex] inches. The area of a rectangle is length × width:
area = length × width
= 10 in. x 5[tex]\frac{1}{3}[/tex] in.
= 53[tex]\frac{1}{3}[/tex] sq. in. ( square inches)
Part F: The ratio is 1 square inch to 100 square yards
EX: The area of the football field in the scale drawing is 53[tex]\frac{1}{3}[/tex] square inches.
The area of the actual football field is 5,333[tex]\frac{1}{3}[/tex] square yards.
The calculation for the ratio of the scaled area to the actual area is
53[tex]\frac{1}{3}[/tex] sq. in. / 5,333[tex]\frac{1}{3}[/tex] sq. yd. = 1 sq. in. / 100 sq. yd.
Step-by-step explanation:
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