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The data show the number of viewers for television stars with certain salaries. Find the regression​ equation, letting salary be the independent​ (x) variable. Find the best predicted number of viewers for a television star with a salary of ​$33 million. Is the result close to the actual number of​ viewers, 3.03.0 ​million? Use a significance level of 0.05.

Sagot :

Answer:

y = 5.064 - 0.010x

Here, in this question x = 33

y = 4.734 million views

In this question data is missing and I filled it out and calculated the questions accordingly. Please refer to the attachment for the data calculated.

Step-by-step explanation:

First of all, this question is incomplete. It lacks the data needed to calculate the required things.

So, I  figured out the question and I will try my best to solve the question at hand.

I have calculated the some data sheet in excel. Please refer to the attachment for that data.

let a be the salaries

b be the viewers

[tex]S_{aa}[/tex] = ∑[tex]a^{2}[/tex]  - [tex]\frac{ Summtion a^{2} }{n}[/tex]

[tex]S_{aa}[/tex] = 7522.8571

[tex]S_{bb}[/tex] = ∑[tex]b^{2}[/tex]  - [tex]\frac{ Summtion b^{2} }{n}[/tex]

[tex]S_{bb}[/tex] = 47.1943

[tex]S_{ab}[/tex] = ∑[tex]ab^{}[/tex]  - [tex]\frac{ Summtion a x Summation b^{} }{n}[/tex]

[tex]S_{ab}[/tex] = -76.8286

Now the slope of the required regression equation is:

Slope =  [tex]S_{ab}[/tex]/[tex]S_{aa}[/tex] = -76.8286/7522.8571 = -0.010

And the intercept of the required regression equation:

intercept = [tex]\frac{1}{n}[/tex] x (∑b - slope x ∑a) = 5.064

So, the regression equation will be:

y = intercept + slope x

y = 5.064 - 0.010x

Here, in this question x = 33

y = 5.064 - 0.010 (33)

y = 4.734 million views

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