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The daily output at a plant manufacturing chairs is

approximated by the function

f(L,K) = 453KL 3/5 chairs

where L is the size of the labor force measured in hundreds

of worker-hours and K is the daily capital investment in

thousands of dollars. If the plant manager has a daily budget

of $13,000 and the average wage of an employee is $9.00

per hour, what combination of worker-hours (to the nearest

hundred) and capital expenditures (to the nearest thousand)

will yield maximum daily production?

Sagot :

Complete Question

The daily output at a plant manufacturing chairs is  approximated by the function

[tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex] chairs

where L is the size of the labor force measured in hundreds

of worker-hours and K is the daily capital investment in  thousands of dollars. If the plant manager has a daily budget  of $13,000 and the average wage of an employee is $9.00  per hour, what combination of worker-hours (to the nearest  hundred) and capital expenditures (to the nearest thousand)  will yield maximum daily production?

a)200 worker-hours and $9000 in capital expenditure

b)1100 worker-hours and $3000 in capital expenditure

c)500 worker-hours and $8000 in capital expenditure

d)900 worker-hours and $5000 in capital expenditure

e)600 worker-hours and $6000 in capital expenditure

f)300 worker-hours and $10,000 in capital expenditure

Answer:

d)900 worker-hours and $5000 in capital expenditure

Step-by-step explanation:

From the question we are told that

Daily output at a plant manufacturing chairs is  approximated by the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]

Daily budget  of $13,000

Average wage of an employee is $9.00  per hour

a) Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to for (a)

Mathematically solving with L=200 K=9000

[tex]f(L=200,K=9000) = (45\sqrt[3]{9000})200^3^/^5[/tex]

[tex]f(L=200,K=9000) = 45*20.8*24[/tex]

[tex]f(L=200,K=9000) = 22464[/tex]

b)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to for (b)

Mathematically solving with L=1100 K=3000

[tex]f(L=1100,K=3000) = (45\sqrt[3]{3000})1100^3^/^5[/tex]

[tex]f(L=1100,K=3000) = 45*14.4*66.8[/tex]

[tex]f(L=1100,K=3000) = 43286.4[/tex]

c)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (c)

Mathematically solving with L=500 K=8000

[tex]f(L=500,K=8000) = (45*\sqrt[3]{8000})*500^3^/^5[/tex]

[tex]f(L=500,K=8000) = 45*20*41.63[/tex]

[tex]f(L=500,K=8000) =37467[/tex]

d)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (d)

Mathematically solving with L=900 K=5000

[tex]f(L=900,K=5000) = (45*\sqrt[3]{5000})*900^3^/^5[/tex]

[tex]f(L=900,K=5000) = 45*17.09*59.2[/tex]

[tex]f(L=900,K=5000) =45577.88[/tex]

e)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (e)

Mathematically solving with L=600 K=6000

[tex]f(L=600,K=6000) = (45\sqrt[3]{6000})600^3^/^5[/tex]

[tex]f(L=600,K=6000) = 45*18.17*46.4[/tex]

[tex]f(L=600,K=6000) =37974[/tex]

f)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (e)

Mathematically solving with L=600 K=6000

[tex]f(L=300,K=10,000) = (45*\sqrt[3]{10,000})*300^3^/^5[/tex]

[tex]f(L=300,K=10,000) = 45*21.5*30.6[/tex]

[tex]f(L=300,K=10,000) = 29704.2[/tex]

Therefore the function f shows maximum at L=900 K=5000

Giving the correct answer to be

d)900 worker-hours and $5000 in capital expenditure