Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

In an interval whose length is z seconds, a body moves (32z + 2z^ 2 ) ft. What is the average speed v of the body in this interval?

Sagot :

nuhulawal20

This question is incomplete, the complete question is;

In an interval whose length is z seconds, a body moves (32z + 2z²) ft.

What is the average speed v of the body in this interval?

Answer: the average speed v of the body in this interval is 32 + 2z ft/s

Step-by-step explanation:

Given that;

Length of travel = z seconds

also the body moves (32z + 2z²) ft

i.e

distance travelled = (32z + 2z²) ft

average speed v of the body in this interval = ?

Now to get the Average Speed

we simply say;

Average Speed V =  (32z + 2z²) / z

Average Speed V = 32 + 2z ft/s

Therefore the average speed v of the body in this interval is 32 + 2z ft/s

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.