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Help Plz Special Right Triangles Help!!!!

Help Plz Special Right Triangles Help class=

Sagot :

Answer:

c

Step-by-step explanation:

in upper triangle:

Tan60=p/b

    √3=a/6

∴a=6√3

again, sin60=p/h

√3 /2=6√3 /b

∴b=12

now, taking down triangle:

cos45=h/b

1/√2 =12/c

∴c=6√2                            

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