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Practice
1. Nitrogen and oxygen
en and oxygen in their liquid states have densities only 0.8 and 0.9
water. Atmospheric pressure is due primarily to the weight of nitro-
and oxygen gas in the air. If the atmosphere liquefied, would its depth
be greater or less than 10.3 m?​


Sagot :

Answer:

In both cases the height is greater than 10.3 m

Explanation:

Pressure is defined by the relationship

       P = F / A

in this case the force is the weight of the two gases

       F = W = m g

If we use the definition of density

      ρ = m / V

      V = A h

      m = ρ A h

we substitute

       P = ρ g h

       h = [tex]\frac{P}{\rho g}[/tex]

For this case the density of the gases is

       ρ' = 0.9 [tex]\rho_{water}[/tex]

       h =[tex]\frac{P}{0.9 \ \rho_{water} g}[/tex]

we calculate

     ρ’= 0.9 \rho_{water}

     h = 1 105 / (0.9 1000 9.8)

     h = 11.3 m

      ρ’= 0.8 \rho_{water}

       h = 1 105 / (0.8 1000 9.8

       h = 12.8 m

In both cases the height is greater than 10.3 m