Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
I would use substitution.
So y=x-1 and 2x+y=8
Substitute y=x-1 in for y
2x+(x-1)=8
Simply
= 3x -1=8
Bring the one to the other side
3x=9
Divide
X=3
Plug x into y=x-1
Y=(3)-1
Y=2
Check with the other equation
2(3)+(2)=8
6+2 =8
X=3
Y=2
You can also do elimination.
Y=x-1 and 2x+y=8
Subtract c from the first equation
-x+y=-1 and 2x+y=8
Those are your equations.
-1(-x+y)=-1
= x-y=1
2x+y=8
The y’s would cancel and you would add down so this is your new equation
3x=9
X=3
You then plug in the 3 for x
And find y
Y=(3)-1
Y=2
So y=x-1 and 2x+y=8
Substitute y=x-1 in for y
2x+(x-1)=8
Simply
= 3x -1=8
Bring the one to the other side
3x=9
Divide
X=3
Plug x into y=x-1
Y=(3)-1
Y=2
Check with the other equation
2(3)+(2)=8
6+2 =8
X=3
Y=2
You can also do elimination.
Y=x-1 and 2x+y=8
Subtract c from the first equation
-x+y=-1 and 2x+y=8
Those are your equations.
-1(-x+y)=-1
= x-y=1
2x+y=8
The y’s would cancel and you would add down so this is your new equation
3x=9
X=3
You then plug in the 3 for x
And find y
Y=(3)-1
Y=2
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
