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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=−16x^{2} + 157x+104

Sagot :

Can you send a picture of it? Then maybe I can help you answer it.
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