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PLEASE HELP!!!
Suppose a normal distribution has a mean of 50 and a standard deviation of
3. What is P(x<44)?
O A. 0.16
O B. 0.84
O C. 0.975
O D. 0.025


Sagot :

To solve this problem, we can simply use the formula of normal distribution and substitute the values where required.

The value of P(x <= 44) is 0.025 which is option D

Probability

Given the value of the mean, normal distribution and standard deviation, we can calculate where the value lies

Data;

  • Mean = 50
  • S.D = 3
  • X = 44

But we know that

[tex]z = \frac{x- \mu}{\sigma}[/tex]

Let's substitute the values of x, standard deviation and mean into the equation above

[tex]z = \frac{x-\mu}{\sigma} \\z = \frac{44-50}{3} =-2[/tex]

Solving this further;

[tex]P(z\leq -2) = \frac{1}{2} - \frac{1}{2}(0.9545)\\p(z\leq -2) = 0.025[/tex]

The value of P(x <= 44) is 0.025 which is option D

Learn more on normal distribution here;

https://brainly.com/question/16022092

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