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If an elevator is moving at a speed of 5 m/s and the person in it is 82 kg what is the person’s kinetic energy?

Sagot :

Answer:

KE 1025J

[tex] \frac{1}{2} m {v}^{2} \\ [/tex]

Explanation:

[tex] \frac{1}{2} \times 82 \times {5}^{2} [/tex]

1025J