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PLEASE HELP ME!!
Write an equation of the line that passes through (4,−1) and is parallel to the line y=3x+7.
An equation of the parallel line is _

Sagot :

Answer:

y = 3x-13

Step-by-step explanation:

For parallel lines, their slopes/gradients of the line are equal.

Given the parallel line, y = 3x+7 implies the slope say m1 = 3.

Hence, the slope of the new line say m2 should be 3 too.

Now, substitute the point (4,-1) into the general formula y-y1 = m2 (X-X1)

This implies, y - (-1) = 3 (X-4) = 3X-12

                     y + 1 = 3X - 12.   Subtract 1 from both sides gives y = 3x - 13

Therefore, the equation of the new parallel line is y = 3x - 13

                   

                   

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