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Sagot :
Answer:
B)10.0 dm3
Explanation:
Now we have to apply Gay-Lussac's law which states that gases combine in simple volumes provided the temperature and pressure remain constant.
2NO(g) + O2(g) ------>2NO
combining volumes 2 : 1 : 2
Volumes before reaction 8.0 6.0 0.0
Reacting volumes 8.0 4.0 8.0
Volumes after reaction - 2.0 8.0
Therefore;
Total volume after reaction = 2.0 + 8.0 = 10.0 dm^3
The volume of the mixture after the reaction is 10 dm³
The correct answer to the question is Option B. 10 dm³
The above is simply a demonstration of Gay-Lussac' law. The volume of the mixture after the reaction can be obtained as follow:
2NO(g) + O₂ —> 2NO(g)
Combining Vol: 2 dm³ : 1 dm³ : 2 dm³
Before reaction: 8 dm³ : 6 dm³ : 0
During reaction: 8 dm³ : 4 dm³ : 8 dm³
After reaction: 0 dm³ : 2 dm³ : 8 dm³
The Volume after the reaction = 2 + 8 = 10 dm³
Learn more about Gay-Lussac's law:
https://brainly.com/question/16984126
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