Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

An ideal spring with a constant of 150 N/m is compressed 14 cm. How much energy is stored in the spring?

Sagot :

Space

Answer:

[tex]\displaystyle U_E = 1.47 \ J[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Physics

Unit 0

  • Unit Conversion: 100 cm = 1 m
  • 1 N/m (Newton per meter) = 1 J (Joule)

Energy

Elastic Potential Energy Formula: [tex]\displaystyle U_E = \frac{1}{2} k \Delta x^2[/tex]

  • k is spring constant
  • Δx is displacement from equilibrium

Explanation:

Step 1: Define

k = 150 N/m

Δx = 14 cm

Step 2: Identify Conversions

Unit Conversion 100 cm = 1 m

Step 3: Convert

Δx = 14 cm = 0.14 m

Step 4: Find Energy

  1. Substitute [EPE]:                    [tex]\displaystyle U_E = \frac{1}{2} (150 \ N/m)(0.14 \ m)^2[/tex]
  2. Exponents:                             [tex]\displaystyle U_E = \frac{1}{2} (150 \ N/m)(0.0196 \ m^2)[/tex]
  3. Multiply:                                 [tex]\displaystyle U_E = (75 \ N/m)(0.0196 \ m^2)[/tex]
  4. Multiply:                                 [tex]\displaystyle U_E = 1.47 \ N/m[/tex]
  5. Redefine:                               [tex]\displaystyle U_E = 1.47 \ J[/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.