Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Your answer is c. 3/5. You just add 2/5 and 1/5 together (your denominator never changes when you are adding the same denominator). You would basically just do 2 + 1=3
travel distance on first day - 1/5 (0.2)
travel distance on second day - 2/5 (0.4)
total distance traveled on two days - 1/5+2/5 (or) 0.2+0.4
1/5+2/5 (or) 0.2+0.4
[as the two denominators are same we can just add the numerators]
3/5 (or) 0.6
Therefore, the family traveled 3/5 (0.6) on two days. So the answer is C. 3/5
travel distance on second day - 2/5 (0.4)
total distance traveled on two days - 1/5+2/5 (or) 0.2+0.4
1/5+2/5 (or) 0.2+0.4
[as the two denominators are same we can just add the numerators]
3/5 (or) 0.6
Therefore, the family traveled 3/5 (0.6) on two days. So the answer is C. 3/5
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.