Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Your answer is c. 3/5. You just add 2/5 and 1/5 together (your denominator never changes when you are adding the same denominator). You would basically just do 2 + 1=3
travel distance on first day - 1/5 (0.2)
travel distance on second day - 2/5 (0.4)
total distance traveled on two days - 1/5+2/5 (or) 0.2+0.4
1/5+2/5 (or) 0.2+0.4
[as the two denominators are same we can just add the numerators]
3/5 (or) 0.6
Therefore, the family traveled 3/5 (0.6) on two days. So the answer is C. 3/5
travel distance on second day - 2/5 (0.4)
total distance traveled on two days - 1/5+2/5 (or) 0.2+0.4
1/5+2/5 (or) 0.2+0.4
[as the two denominators are same we can just add the numerators]
3/5 (or) 0.6
Therefore, the family traveled 3/5 (0.6) on two days. So the answer is C. 3/5
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.