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How many moles are in 1.806 x 1024 molecules of bromine?

Sagot :

Space

Answer:

2.999 mol Br

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

1.806 × 10²⁴ molecules Br

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[tex]\displaystyle 1.806 \cdot 10^{24} \ molecules \ Br(\frac{1 \ mol \ Br}{6.022 \cdot 10^{23} \ molecules \ Br} )[/tex] = 2.999 mol Br

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

Our final answer is already in 4 sig figs, so there is no need to round.

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf About \ 2.999 \ moles \ of \ bromine}}[/tex]

Explanation:

To convert from moles to molecules, we must use Avogadro's Number.

[tex]6.022*10^{23}[/tex]

This tells us the number of particles (atoms, molecules, ions, etc) in 1 mole. In this problem, the particles are molecules of bromine in 1 mole of bromine.

[tex]6.022*10^{23} \ molecules \ Br / 1 \ mol \ Br[/tex]

1. Convert from moles to molecules

Use Avogadro's number as a fraction or ratio.

[tex]\frac{6.022 *10^{23} \ molecules \ Br}{1 \ mol \ Br}[/tex]

Multiply this fraction by the given number of bromine molecules.

[tex]1.806 *10^{24} molecules \ Br *\frac{6.022 *10^{23} \ molecules \ Br}{1 \ mol \ Br}[/tex]

Flip the fraction so the molecules of bromine can cancel out.

[tex]1.806 *10^{24} \ molecules \ Br* \frac{1 \ mol \ Br}{6.022 *10^{23} \ molecules \ Br}[/tex]

[tex]1.806 *10^{24} * \frac{1 \ mol \ Br}{6.022 *10^{23}}[/tex]

Multiply and condense the expression into 1 fraction.

[tex]\frac{1.806 *10^{24} \ mol \ Br}{6.022 *10^{23} }[/tex]

Divide.

[tex]2.999003653 \ mol \ Br[/tex]

2. Round

The original measurement, 1.806*10^24 has 4 significant figures (1, 8, 0, and 6). We must round our answer to 4 sig figs. For the answer we found, that is the thousandth place.

[tex]2.999003653 \ mol \ Br[/tex]

The 0 in the ten-thousandth place tels us to leave the 9 in the thousandth place.

[tex]\approx 2.999 \ mol \ Br[/tex]

There are about 2.999 moles of bromine in 2.806 *10^23 molecules.

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