Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
[tex]\displaystyle x=\frac{1\pm i\sqrt{5}}{6}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Equality Properties
Algebra I
- Standard Form: ax² + bx + c = 0
- Quadratic Formula: [tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
Algebra II
- Imaginary Roots: √-1 = i
Step-by-step explanation:
Step 1: Define
6x² = 2x - 1
Step 2: Rewrite
- Subtract 2x on both sides: 6x² - 2x = -1
- Add 1 to both sides: 6x² - 2x + 1 = 0
Step 3: Identify Variables
a = 6
b = -2
c = 1
Step 4: Solve for x
- Substitute [QF]: [tex]\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(6)(1)} }{2(6)}[/tex]
- Exponents: [tex]\displaystyle x=\frac{2\pm\sqrt{4-4(6)(1)} }{2(6)}[/tex]
- Multiplication: [tex]\displaystyle x=\frac{2\pm\sqrt{4-24} }{12}[/tex]
- (Square Root) Subtract: [tex]\displaystyle x=\frac{2\pm\sqrt{-20} }{12}[/tex]
- Factor: [tex]\displaystyle x=\frac{2\pm \sqrt{-1} \sqrt{20} }{12}[/tex]
- Simplify: [tex]\displaystyle x=\frac{2\pm 2i\sqrt{5} }{12}[/tex]
- Factor GCF: [tex]\displaystyle x=\frac{2(1\pm i\sqrt{5} )}{12}[/tex]
- Simplify: [tex]\displaystyle x=\frac{1\pm i\sqrt{5}}{6}[/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.