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Sagot :
Answer: 1/36
Explanation:
The probability of rolling a "2" is 1/6
The probability of rolling a "4" is also 1/6
Multiplying those fractions leads to (1/6)*(1/6) = 1/36. We can multiply the probabilities because the events are independent. Each dice roll does not affect any others.
The probability of rolling a 2 the first time and a 4 the second time is 1/36
There are 6 faces on a die.
Of these 6 faces, one of them is 2 and one of them is 4
So, the probabilities of rolling a 2 and a 4 are:
P(2) = 1/6
P(4) = 1/6
The probability of rolling a 2 the first time and a 4 the second time is calculated as follows:
[tex]\mathbf{Pr = P(2) \times P(4)}[/tex]
This gives
[tex]\mathbf{Pr = \frac 16 \times \frac 16}[/tex]
Multiply
[tex]\mathbf{Pr = \frac 1{36}}[/tex]
Hence, the probability of rolling a 2 the first time and a 4 the second time is 1/36
Read more about probabilities at:
https://brainly.com/question/11234923
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