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Solve x^2- 2x - 4 = 0

Sagot :

Space

Answer:

[tex]\displaystyle x= 1\pm \sqrt{5}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: [tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Step-by-step explanation:

Step 1: Define

x² - 2x - 4 = 0

Step 2: Identify Variables

a = 1

b = -2

c = -4

Step 3: Solve for x

  1. Substitute [QF]:                    [tex]\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(1)(-4)} }{2(1)}[/tex]
  2. Exponents:                           [tex]\displaystyle x=\frac{2\pm\sqrt{4-4(1)(-4)} }{2(1)}[/tex]
  3. Multiply:                                [tex]\displaystyle x=\frac{2\pm\sqrt{4+16} }{2}[/tex]
  4. Add:                                      [tex]\displaystyle x=\frac{2\pm\sqrt{20} }{2}[/tex]
  5. Simplify:                               [tex]\displaystyle x=\frac{2\pm 2\sqrt{5} }{2}[/tex]
  6. Factor:                                 [tex]\displaystyle x=\frac{2(1\pm \sqrt{5}) }{2}[/tex]
  7. Divide:                                 [tex]\displaystyle x= 1\pm \sqrt{5}[/tex]
almafalaniew

Answer:

yes

Step-by-step explanation:

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