Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Solve x^2- 2x - 4 = 0

Sagot :

Space

Answer:

[tex]\displaystyle x= 1\pm \sqrt{5}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: [tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Step-by-step explanation:

Step 1: Define

x² - 2x - 4 = 0

Step 2: Identify Variables

a = 1

b = -2

c = -4

Step 3: Solve for x

  1. Substitute [QF]:                    [tex]\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(1)(-4)} }{2(1)}[/tex]
  2. Exponents:                           [tex]\displaystyle x=\frac{2\pm\sqrt{4-4(1)(-4)} }{2(1)}[/tex]
  3. Multiply:                                [tex]\displaystyle x=\frac{2\pm\sqrt{4+16} }{2}[/tex]
  4. Add:                                      [tex]\displaystyle x=\frac{2\pm\sqrt{20} }{2}[/tex]
  5. Simplify:                               [tex]\displaystyle x=\frac{2\pm 2\sqrt{5} }{2}[/tex]
  6. Factor:                                 [tex]\displaystyle x=\frac{2(1\pm \sqrt{5}) }{2}[/tex]
  7. Divide:                                 [tex]\displaystyle x= 1\pm \sqrt{5}[/tex]

Answer:

yes

Step-by-step explanation: