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A 200N lamp is suspended from three cables as shown in the figure below. Find the tensions in each of the three cables.

Sagot :

Answer:

66.6N

Explanation:

Step one;

given data

the mass of the lamp = 200N

we are told that it is suspended by 3 cables.

Now we know that the weight will be distributed equally on the cables

Step two:

so, let the tension in each cable be T

T+T+T= 200

3T=200

T=200/3

T=66.6N

The tenion on each cable is 66.6N