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Find the 22nd term of the sequence described by the
explicit formula:
f(n) = 8 + 3(n - 1)


Find The 22nd Term Of The Sequence Described By The Explicit Formula Fn 8 3n 1 class=

Sagot :

Answer:

[tex]\boxed{\boxed{\pink{\bf \leadsto The \ 22nd \ term \ is \ 71. }}}[/tex]

Step-by-step explanation:

Given that the nth term of the Arthemetic Sequence is given by :-

[tex]\implies f(n) = 8 + 3(n-1) [/tex]

And we need to find the 22nd term .

So in place of n substitute 22 .

[tex]\bf\implies f(n) = 8 + 3(n-1) \\\\\bf\implies f_{22} = 8 + 3(22-1) \\\\\bf\implies f_{22} = 8 + 3\times 21 \\\\\bf\implies f_{22} = 8 + 63 \\\\\bf\boxed{\bf\implies f_{22} = 71 }[/tex]

Hence the 22nd term is 71 .