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Write the equation of a line in Point-Slope form that has a slope of -2/3 and
passes through the point (-1,3).


Sagot :

Answer:

The equation of a line in Point-Slope form is y -3=[tex]-\frac{2}{3}[/tex] *(x+1)

Step-by-step explanation:

Linear equations can take various forms, such as the point-slope formula. This formula gives the slope of a line and the coordinates of a point on it. The point-slope form of a linear equation is written as:

y - y1= m*(x-x1)

In this equation, m is the slope and (x1, y1) are the coordinates of the point.

In this case, you know that the line has a slope of [tex]-\frac{2}{3}[/tex] and  passes through the point (-1,3). This is, m=[tex]-\frac{2}{3}[/tex] and (x1;y1)=(-1;3). Replacing:

y -3=[tex]-\frac{2}{3}[/tex] *(x-(-1))

This is:

y -3=[tex]-\frac{2}{3}[/tex] *(x+1)

The equation of a line in Point-Slope form is y -3=[tex]-\frac{2}{3}[/tex] *(x+1)