Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
[tex]x = 4[/tex]
[tex]y = -5[/tex]
Step-by-step explanation:
Given
[tex]-10x^2+80x+y=155[/tex]
[tex]5x^2-40x+y=-85[/tex]
Required
Solve by substitution
Make y the subject in [tex]5x^2-40x+y=-85[/tex]
[tex]5x^2-40x+y=-85[/tex]
[tex]y = -5x^2 + 40x - 85[/tex]
Substitute [tex]y = -5x^2 + 40x - 85[/tex] in the first equation
[tex]-10x^2+80x+y=155[/tex]
[tex]-10x^2 + 80x -5x^2 + 40x - 85 = 155[/tex]
Collect Like Terms
[tex]-5x^2-10x^2 + 80x + 40x - 85 - 155=0[/tex]
[tex]-15x^2 + 120x-240=0[/tex]
Divide through by -15
[tex]x^2 -8x + 16 = 0[/tex]
[tex]x^2 - 4x - 4x + 16 = 0[/tex]
[tex]x(x - 4) - 4(x - 4) = 0[/tex]
[tex](x - 4)(x - 4) = 0[/tex]
[tex]x - 4\ = 0[/tex] or [tex]x - 4\ = 0[/tex]
[tex]x = 4[/tex] or [tex]x = 4[/tex]
[tex]x = 4[/tex]
Substitute 4 for x in [tex]y = -5x^2 + 40x - 85[/tex]
[tex]y = -5(4)^2 + 40 * 4 - 85[/tex]
[tex]y = -5*16 + 40 * 4 - 85[/tex]
[tex]y = -80 + 160 - 85[/tex]
[tex]y = -5[/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.