ullattilaldrin
Answered

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find the value of variable y using appropriate identity (y-5)2-(y-3)2=12
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Sagot :

Answer:

[tex]\\\qquad\quad\displaystyle\sf {:}\longrightarrow (y-5)2-(y-3)2=12 [/tex]

[tex]\\\qquad\quad\displaystyle\sf {:}\longrightarrow 2y-10-2y-6=12[/tex]

[tex]\\\qquad\quad\displaystyle\sf {:}\longrightarrow 2y-2y-10-6=12 [/tex]

[tex]\\\qquad\quad\displaystyle\sf {:}\longrightarrow -16=12 [/tex]

[tex]\\\qquad\quad\displaystyle\sf {:}\longrightarrow y's\:value\:is\:undefined [/tex]

manissaha129

Answer:

[tex] {(y - 5)}^{2} - {(y - 3)}^{2} = 12 \\ = ( {y}^{2} - 10y + 25) - ( {y}^{2} - 6y + 9) = 12 \\ = {y}^{2} - 10y+ 25 - {y}^{2} + 6y - 9 = 12 \\ = - 4y + 16 = 12 \\ = - 4y = 12 - 16 \\ = - 4y = - 4 \\ = y = \frac{ - 4}{ - 4} \\ = \boxed{y = 1}[/tex]

y=1 is the right answer.

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