Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Given that P(x)=x^5-8x^3-x^2+2, what is the remainder when it is divided by x-5?

Sagot :

abidemiokin

Answer:

2102

Step-by-step explanation:

The polynomial function P(x)=x^5-8x^3-x^2+2, if it is divided by x-5, first we need to get x from the divisor as shown

since d(x) = x-5

x-5 = 0

x = 5

Substitute x = 5 into the expression to get the remainder

P(x)=x^5-8x^3-x^2+2

P(5)=(5)^5-8(5)^3-(5)^2+2

P(5) = 3125-1000-25+2

p(5) = 2100+2

P(5) = 2102

Hence the remainder is 2102

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.