Answered

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Given that P(x)=x^5-8x^3-x^2+2, what is the remainder when it is divided by x-5?

Sagot :

abidemiokin

Answer:

2102

Step-by-step explanation:

The polynomial function P(x)=x^5-8x^3-x^2+2, if it is divided by x-5, first we need to get x from the divisor as shown

since d(x) = x-5

x-5 = 0

x = 5

Substitute x = 5 into the expression to get the remainder

P(x)=x^5-8x^3-x^2+2

P(5)=(5)^5-8(5)^3-(5)^2+2

P(5) = 3125-1000-25+2

p(5) = 2100+2

P(5) = 2102

Hence the remainder is 2102

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