rafa1392004
Answered

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Does anyone knows how to solve this?

Does Anyone Knows How To Solve This class=

Sagot :

adiya76

Answer:

This is the answer do it fast. Ok

View image adiya76

Answer:

see explanation

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = x² - 8x + 13 ← is in standard form

with a = 1 and b = - 8 , then

[tex]x_{vertex}[/tex] = - [tex]\frac{-8}{2}[/tex] = 4

Substitute x = 4 into the equation for corresponding value of y

y = 4² - 8(4) + 13 = 16 - 32 + 13 = - 3

Vertex = (4, - 3 )

The axis of symmetry is a vertical line passing through the vertex with equation

x = 4 ← equation of axis of symmetry

To determine direction of opening

• If a > 0 then graph opens up

• If a < 0 then graph opens down

Here a = 1, thus graph opens up

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