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find quotient and remainder b)diving 2x^3- 5x² +x+2
by x - 2


photo of the answer in notebook​

Sagot :

Given:

Dividend = [tex]2x^3-5x^2+x+2[/tex]

Divisor = [tex]x-2[/tex]

To find:

The quotient and remainder.

Solution:

We have,

Dividend = [tex]2x^3-5x^2+x+2[/tex]

Divisor = [tex]x-2[/tex]

Divide [tex]2x^3-5x^2+x+2[/tex] by [tex]x-2[/tex] as shown in the below picture.

Dividing [tex]2x^3-5x^2+x+2[/tex] by [tex]x-2[/tex], we get

[tex]Quotient=2x^2-x-1[/tex]

[tex]Remainder=0[/tex]

Therefore, [tex]Quotient=2x^2-x-1[/tex] and [tex]Remainder=0[/tex].

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