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Find the measure of the acute angle that line y=1/3x+4 makes with a horizontal line. Round your answer to the nearest tenth.

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Sagot :

Answer:

The measure of the acute angle is 18.4°

Step-by-step explanation:

The angle between a line of equation y = m x + b and the positive part of the x-axis is Ф = [tex]tan^{-1}[/tex](m), which means tan Ф = m, where m is the slope of the line

Let us use this rule to solve the question

∵ A line of equation y = [tex]\frac{1}{3}[/tex] x + 4 makes with a horizontal line an acute ∠

→ Compare the equation of the line by the form of the equation above

m = [tex]\frac{1}{3}[/tex]

→ Assume that the acute angle is Ф

∴ The acute angle between the line and the horizontal line is Ф

→ By using the rule above

∵ tan Ф = m

tan Ф = [tex]\frac{1}{3}[/tex]

→ Use [tex]tan^{-1}[/tex] to find Ф

Ф =  [tex]tan^{-1}[/tex] ( [tex]\frac{1}{3}[/tex] )

∴ Ф = 18.43494882

→ Round it to the nearest tenth

Ф = 18.4°

The measure of the acute angle is 18.4°