Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

a certain componnt for newly developed electronic disel engine is considered to be defective if its diameter is less than 8.0 mm or greater than 10.5mm. the distribution of the diameters of these parts is known to be normal with mean of 9.0 mm and standard deviation of 1.5 mm.if a component is randomly selected what is probability that it will be defective?

Sagot :

Answer:

The probability is 0.58992 or simply 0.59

Step-by-step explanation:

We start by getting the z-scores of the diameter

we have this as follows;

Mathematically;

z-score = (x-mean)/SD

mean = 9.0 mm

SD = 1.5 mm

For 8.00 mm, we have

z = (8-9)/1.5 = -0.67

For 10.5 mm, we have

z = (10.5-9)/1.5 = 1

So the probability we want to calculate is;

P( 1 < x < -0.67)

we can calculate this using the standard normal distribution table

We have this as ;

P( x < -0.67) - P( x > 1) = 0.58992

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.