Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
The test statistic 't' = 0.68 < 2.1314 at 0.05 level of significance
Null Hypothesis is accepted
There is no sufficient evidence to support the claim that the boards are either too long or too short
Step-by-step explanation:
Step(i):-
Mean of the Population (μ) = 2857.0 millimetres
size of the sample 'n' = 16
Mean of the sample (x⁻) = 2858.7 millimetres
The Variance of the sample (S²)= 100.00
Standard deviation of the sample (S) = √100 =10
Degrees of freedom = n-1 =16-1 =15
Level of significance =0.05
Tabulated value = [tex]t_{\frac{0.05}{2} , 15} = t_{0.025,15} = 2.1314[/tex]
Step(ii):-
Null Hypothesis :H₀ : There is no sufficient evidence to support the claim that the boards are either too long or too short
Alternative Hypothesis: H₁:There is sufficient evidence to support the claim that the boards are either too long or too short
Test statistic
[tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]
[tex]t = \frac{2858.7 -2857}{\frac{10}{\sqrt{16} } }[/tex]
t = 0.68
The calculated value = 0.68 < 2.1314 at 0.05 level of significance
Null Hypothesis is accepted
Final answer:-
There is no sufficient evidence to support the claim that the boards are either too long or too short
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
