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Matrices C and D are shown below C= 2 1 0 0 3 4 0 2 1 D= a b -0.4 0 -0.2 0.8 0 0.4 -0.6 what values of a and b will make the equation CD = l true?

Sagot :

The question is incomplete. Here is the complete question

Matrices C and D are shown below:

[tex]C=\left[\begin{array}{ccc}2&1&0\\0&3&4\\0&2&1\end{array}\right][/tex]     [tex]D=\left[\begin{array}{ccc}a&b&-0.4\\0&-0.2&0.8\\0&0.4&-0.6\end{array}\right][/tex]

What values of a and b will make the equation CD = I true?

(i) a = 0.5

  b = 0.1

(ii) a = 0.1

    b = 0.5

(iii) a = -0.5

    b = -0.1

Answer: (i) a = 0.5

                  b = 0.1

Step-by-step explanation: Identity Matrix (I) is a n x n square matrix with the number 1 on the main diagonal and 0 everywhere else.

The question asks for multiplication of matrices, i.e.:

[tex]\left[\begin{array}{ccc}2&1&0\\0&3&4\\0&2&1\end{array}\right][/tex]  .   [tex]\left[\begin{array}{ccc}a&b&-0.4\\0&-0.2&0.8\\0&0.4&-0.6\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right][/tex]

To multiply matrices, the number of columns of the 1st matrix must be the same as the number of rows of the 2nd.

Matrix C is a 3x3 square matrix and so is matrix D, so, values of a and b:

[tex]2a=1[/tex]                           [tex]2b-0.2=0[/tex]

[tex]a=\frac{1}{2}[/tex]                            [tex]2b=0.2[/tex]

a = 0.5                          [tex]b=0.1[/tex]

For the equation CD=I be true, a and b has to be 0.5 and 0.1, respectively.