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Let q= (15,-3), r= (-5,8), and S = (10.-1). What is r- 9+2s? (0.3) 0 (0.9) 0 (40.3) 0 (40.-13)​

Sagot :

JeanaShupp

Answer: The value of  r- q+2s is (0,9).

Step-by-step explanation:

Given: q= (15,-3), r= (-5,8), and S = (10,-1)

To find: r- q+2s

Consider r- q+2s = (-5,8) - (15,-3) + 2x (10,-1)

= (-5,8) - (15,-3) +(2 x 10,  2 x -1)  [ a(b,c) = (ab, ac)]

= (-5, 8) - (15,-3) + (20,-2)

= (-5-15+20, 8-(-3)+(-2))      [(a,b)+(c,d)= (a+c, b+d)]

= (-20+20, 8+3-2)

= (0, 9)

Hence, the value of  r- q+2s is (0,9).

Answer:

B

Step-by-step explanation:

I am 99% sure it is B

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