Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

How many moles of NaCl are present in 2.50 L of a 0.070 M solution?


a

2.8 x 10-2 moles of NaCl


b

35.7 moles of NaCl

c

1.75 x 10-4 moles of NaCl


d

0.175 moles of NaCl

Sagot :

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

[tex]M = \dfrac{n}{V(in\ L)}[/tex]

So,

[tex]n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles[/tex]

Therefore, number of moles of NaCl is 0.175 moles.

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.