Answered

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If an instant pot has an internal pressure of 191.0 kPa, temperature of 750.0 K and a volume of 6.5 L, how many moles of gas would be contained inside the instant pot?

Sagot :

sebassandin

Answer:

0.200 mol.

Explanation:

Hello!

In this case, since this case is considered an ideal one (no intermolecular interactions), we can use the following equation:

[tex]PV=nRT[/tex]

Thus, since we know the pressure, temperature and volume, we are able to compute the moles shown below:

[tex]n=\frac{PV}{RT} =\frac{191kPa*\frac{1000Pa}{1kPa} *6.5L*\frac{1m^3}{1000L} }{8.314\frac{Pa*m^3}{mol*K}*750.0K}\\\\n=0.200mol[/tex]

Best regards!

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