Answer:
88.89%
Step-by-step explanation:
Calculation for what is the minimum percentage of quiz scores between 4.8 and 8.4
The calculated minimum percentage value of quiz scores between
First step is to calculate the lower k value using this formula
k=(x1−m)/s
Where:
x1 represent first random value 4.8
x2 represent second random value 8.4
m represent mean 6.6
s represent standard deviation 0.6
Let plug in the formula
k=(4.8−6.6)/0.6
k=−1.8/0.6
k=−3
Second step is to calculate the upper k value
k=(x2−m)/s
k=(8.4−6.6)/0.6
k=1.8/0.6
k=3
Now let calculate the minimum percentage
Using this formula
Minimum percentage=1−1/k^2
Let plug in the formula
Minimum percentage=1−1/3^2
Minimum percentage=1−1/9
Minimum percentage=1−0.1111
Minimum percentage=0.8889*100
Minimum percentage=88.89%
Therefore the minimum percentage of quiz scores between 4.8 and 8.4 is 88.89%
Answer:
75%
Step-by-step explanation:
5.2−6.40.6=−2 and 7.6−6.40.6=2.
This means that 5.2 lies 2 standard deviations below the mean and 7.6 lies 2 standard deviations above the mean.
According to Chebyshev's Theorem, at least 75% of data values lie within 2 standard deviations of the mean.
Therefore, we can say that 75% is the minimum percentage of quiz scores between 5.2 and 7.6.
