Answered

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A small glass bead has been charged to 8.0 nC (nano-Coulombs). What is the magnitude of the electric field 2.0 m from the center of the bead

Sagot :

Given :

Charge on glass bead, Q = 8 nC .

To Find :

The magnitude of the electric field 2.0 m from the center of the bead.

Solution :

Electric field at position r is given by :

[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]

Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .

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