Answered

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What is the specific heat of a 123 g substance that requires 4.56 J of heat in

order to increase its temperature by 12.32 °C?

A) 0.00301 J/g °C

B) 0.457 J/g °C

0 6910 J/g °C

D) 2.19 J/g °C

E) 0.0220 J/g°C

Sagot :

Answer:  A. [tex]0.00301J/g^0C[/tex]

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed  = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,[tex]\Delta T=T_f-T_i=12.32^0C[/tex]

Putting in the values, we get:

[tex]4.56J=123g\times c\times 12.32^0C[/tex]

[tex]c=0.00301J/g^0C[/tex]

The specific heat of a 123 g substance that requires 4.56 J of heat in  order to increase its temperature by 12.32 °C is [tex]0.00301J/g^0C[/tex]

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