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Sagot :
Answer:
[tex]P(X\geq 1)= 1 - 0.0497 8 =0.95022[/tex]
Step-by-step explanation:
Step(i):-
Let 'X' be the random variable in Poisson distribution
Mean of the Poisson distribution λ or ∝ = 3 per (cm³)
Given n = 5 samples
[tex]P(X=r) = \frac{e^{-\alpha }\alpha ^{r} }{r!}[/tex]
Step(ii):-
The probability that at least one sample will contain one or more bacterial colonies
P(X≥1) = 1-P(X< 1)
= 1 - P( X=0)
[tex]P(X\geq 1)= 1 - \frac{e^{-\alpha }\alpha ^{r} }{r!}[/tex]
[tex]P(X\geq 1)= 1 - \frac{e^{-3 }3 ^{0} }{0!}[/tex]
[tex]P(X\geq 1)= 1 - 0.0497 8 =0.95022[/tex]
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