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A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is the partial pressure of each of the gases

Sagot :

Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

[tex]p_A=x_A\times P_{total}[/tex]

where, [tex]p_A[/tex] = partial pressure of component A

[tex]x_A[/tex] = mole fraction of A

[tex]P_{total}[/tex] = total pressure

mole fraction of Ar = [tex]\frac{\text {Moles of Ar}}{\text {total moles}}=\frac{60.0}{60.0+30.0+10.0}=0.6[/tex]

[tex]p_{Ar}=0.60\times 80.0kPa=48kPa[/tex]

mole fraction of Ne = [tex]\frac{\text {Moles of Ne}}{\text {total moles}}=\frac{30.0}{60.0+30.0+10.0}=0.30[/tex]

[tex]p_{Ne}=0.30\times 80.0kPa=24kPa[/tex]

mole fraction of Kr = [tex]\frac{\text {Moles of Kr}}{\text {total moles}}=\frac{10.0}{60.0+30.0+10.0}=0.10[/tex]

[tex]p_{Kr}=0.10\times 80.0kPa=8kPa[/tex]

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