Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

WILL MARK BRAINLIEST (real answers only please)


A driver on a rural road slams on the brakes to avoid hitting a cow and comes to a stop. Skid marks made while the brakes were applied are 280 feet long. If the tread on the tires produced a coefficient of kinetic friction of 0.3 with the road, how fast was the car moving? 1 m/s=2.237 mph.


35 mph

25 mph

45 mph

50 mph

Sagot :

lublana

Answer:

The car moving with speed 50 mph

Explanation:

We are given that

Distance, s=280 feet=85.3 m

1 feet=0.3048 m

Coefficient of kinetic friction=[tex]\mu_s=0.3[/tex]

1 m/s=2.237 mph

We have to find the speed of car moving.

Speed, v=[tex]\sqrt{2\mu_s gs}[/tex]

Where [tex]g=9.8ms^{-2}[/tex]

Using the formula

Speed of the car,v=[tex]\sqrt{2\times 0.3\times 9.8\times 85.3}[/tex]

Speed of the car,v=22.4 m/s

Speed of the car, v=[tex]22.4\times 2.237\approx 50 mph[/tex]

Hence, the car moving with speed 50 mph

Option  d is true.

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.