Answered

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The wavelength of the violet light emitted from a hydrogen atom is 410.1 nm. This light is a result of electronic transitions between the n = 5 and n = 2 energy levels. How much higher in energy is the n = 5 energy level than the n = 2 energy level?


Select one:

a. 3.000 x 108 J

b. 1.114 x 10-14 J

c. 2.436 x 10-18 J

d. 1.616 x 10-36 J

e. 4.847 x 10-19 J

Sagot :

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Answer:

e. 4.847 x 10-19 J

Explanation:

From the given information:

The equation connecting the photon energy and the wavelength is:

[tex]E_{photon } = \dfrac {hc}{\lambda}[/tex]

where;

[tex]planck's \ constant \ (h)[/tex]= 6.626 * 10 ^{-34} J.s

[tex]velocity \ of \ light \ (c)[/tex] = 3.00 * 10^8 m/s

wavelength [tex]\lambda = 410.1 \ nm \times \dfrac{10^{-9} \ m}{1 \ nm}[/tex]

[tex]\lambda = 4.101 \times 10^{-7} \ m[/tex]

To determine the photon energy of violet light

[tex]E_{photon } = \dfrac {(6.626 \times 10^{-34} J/s ) \times (3.00 \times 10^8 \ m/s) }{4.101 \times 10^{-7} \ m}[/tex]

= 4.847 × 10⁻¹⁹ J

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