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You mix 55 mL of 1.00 M silver nitrate with 25 mL of 0.84 M sodium chloride. What mass of silver chloride should you form

Sagot :

ajeigbeibraheem

Answer:

mass of silver chloride (AgCl) = 3.0135  grams

Explanation:

The chemical equation is:

[tex]AgNO_{3(aq)} + NaCl_{(aq)} \to AgCl_{(s)} + NaNo_3_{aq)}[/tex]

No. of mole  = molarity × volume

For AgNO3:

No. of moles = 1.00 × 0.055

= 0.055 moles

No. of moles of NaCl = 0.84 × 0.025

= 0.021 moles

From the equation:

[tex]1 \ mol e \ of \ AgNO_3 \ react \ with \ 1 \ mole \ o f \ NaCl[/tex]

Therefore, 0.055 moles of AgNO3 react with 0.055 moles of NaCl

Here;

NaCl serves as the limiting reactant

Thus,

1 mole of NaCl will react with AgNO3 to yield 1 mole of AgCl

∴

0.021 moles of NaCl react with AgNO3 to yield 0.021 moles og AgCl

mass of AgCl = no of moles × molar mass

= 0.021 × 143.5

= 3.0135  grams

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