ashelsy261
Answered

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can u guys help me with these two problems?? for the first one I got 76 ,but I don't think is right.
also for the second I got 69 ...​

Can U Guys Help Me With These Two Problems For The First One I Got 76 But I Dont Think Is Right Also For The Second I Got 69 class=

Sagot :

mirai123

Answer:

See below

Step-by-step explanation:

15)

In the right-angle triangle, once one of the angles is 44º, then, the unknown angle is [tex]x[/tex].

[tex]180 = 44 + 90 + x[/tex]

[tex]180 = 134 + x[/tex]

[tex]x= 46[/tex]

The angle [tex]y[/tex] of the other triangle plus the angle [tex]x[/tex] of the right-angle triangle is equal to 90º, therefore they are complementary angles.

So,

[tex]90 = x + y[/tex]

[tex]90 = 46 + y[/tex]

[tex]y=44[/tex]

To find ?, we have

[tex]180 = 58 + 44 +?[/tex]

[tex]180 = 58 + 44 +?[/tex]

[tex]? =78[/tex]

16)

The sum of the internal angles of the triangle with angles 50º and 25º is equal to 180º, therefore, the other angle is

[tex]180 = x + 50 + 25\\180 = x+ 75\\x=105[/tex]

Once the angles are opposite, they are the same. For the triangle with the 36º angle, we have

[tex]180 = 36 + 105 + y[/tex]

[tex]180 = 141+ y[/tex]

[tex]y=39[/tex]

[tex]?=39[/tex]

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