Answer: 0.2273
Step-by-step explanation:
Probability density function for uniform distribution is given by :-
[tex]f(x)=\dfrac{1}{b-a}[/tex], where x is uniformly distributed in [a,b].
Let x denotes the waiting time for this bus.
Given : The waiting time for a bus has a uniform distribution between 2 and 13 minutes.
Probability distribution function of x for interval [2,13] will be :-
[tex]f(x)=\dfrac1{13-2}=\dfrac{1}{11}[/tex]
Required probability : P(x<4.5) = [tex]\int^{4.5}_{2}f(x)\ dx[/tex]
[tex]=\int^{4.5}_{2}\dfrac1{11}\ dx\\\\=\dfrac1{11}[x]^{4.5}_{2}\\\\ = \dfrac1{11}(4.5-2)\\\\=\dfrac1{11}(2.5)\approx0.2273[/tex]
Hence, the probability that the waiting time for this bus is less than 4.5 minutes on a given day = 0.2273
