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Sagot :
Answer: The pressure of the air when compressed is [tex]5.0\times 10^5Pa[/tex]
Explanation:
Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex] (At constant temperature and number of moles)
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = [tex]1.0\times 10^5Pa[/tex]
[tex]P_2[/tex] = final pressure of gas =?
[tex]V_1[/tex] = initial volume of gas = V
[tex]V_2[/tex] = final volume of gas = [tex]\frac{V}{5}[/tex]
[tex]1.0\times 10^5\times V=P_2\times \frac{V}{5}[/tex]
[tex]P_2=5.0\times 10^5Pa[/tex]
Therefore, the pressure of the air when compressed is [tex]5.0\times 10^5Pa[/tex]
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