Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

the weight of an object on the earths surface is 300N. when it is lifted to 3 times the height, its weight will become

Sagot :

Answer:

The weight of the object when it is lifted to 3 times the height is 33.[tex]\overline 3[/tex] N

Explanation:

The given parameters are;

The weight of the object on Earth, W = 300 N

The initial position of the object = On the surface of the Earth

Therefore;

The distance with which the weight is measured = The radius of the Earth, R

By Newton's Law of Gravitation, we have;

[tex]W = G \times \dfrac{M \times m}{R^2}[/tex]

Where;

W = 200 N

G = The universal gravitational constant

M = The mass of the Earth

m = The mass of the object

When the height of the object = 3 × R, the weight of the object, W₂, is given as follows;

[tex]W_2 = G \times \dfrac{M \times m}{(3 \times R)^2} = \dfrac{1}{9} \times G \times \dfrac{M \times m}{ R^2} = \dfrac{1}{9} \times W = \dfrac{1}{9} \times 300 N = 33.\overline 3 \ N[/tex]

Therefore, the weight of the object at 3 times the height, W₂ = 33.[tex]\overline 3[/tex] N