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If NaCl has a mass of 3.2g, what is the volume of chlorine gas at STP?

Sagot :

Willchemistry

Hey there!

Molar mass NaCl = 58.44 g/mol

58.44 g ----------------- 22.4 ( at STP )

3.2 g -------------------- Volume ??

Volume = ( 3.2 x 22.4 )  / 58.44

Volume = 71.68 / 58.44

Volume = 1.226 L

Hope this helps!

Neetoo

Answer:

V = 0.56 L

Explanation:

Given data:

Mass of NaCl = 3.2 g

Volume of chlorine gas = ?

Pressure and temperature = standard

Solution:

Chemical equation:

2NaCl    →     2Na + Cl₂

Number of moles of NaCl:

Number of moles = mass/molar mass

Number of moles = 3.2 g/ 58.44 g/mol

Number of moles = 0.05 mol

Now we will compare the moles of NaCl with chlorine;

              NaCl       :          Cl₂

                 2          :           1

                0.05      :       1/2×0.05 = 0.025 mol

Volume of chlorine:

PV = nRT

V = nRT/P

V = 0.025 mol × 0.0821 atm.L/mol.K × 273 K / 1 atm

V = 0.56 L

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