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If the measure of EF is 90° , what is the arc length of EF?

If The Measure Of EF Is 90 What Is The Arc Length Of EF class=

Sagot :

Answer:

[tex]\huge\boxed{15 \pi \ \text{or} \approx 47.1 \ \text{in.}}[/tex]

Step-by-step explanation:

We can note a couple of relationships in this circle.

The arc length will be a fraction of the circumference. It will be the same fraction of the circumference that the central angle is to the entire circle.

First step: Find the circumference of the circle.

The circumference of any circle can be defined by the formula [tex]2 \pi r[/tex], where r is the radius of the circle. The radius is given to us, 30 in. We can now substitute that into the formula.

  • [tex]2\cdot \pi \cdot 30[/tex]
  • [tex]60 \cdot \pi[/tex]
  • [tex]60\pi[/tex]

So our circumference is 60π.

Second Step: Find the ratio of the central angle of the arc to the total circle degrees

We know that the total amount of degrees in a circle is 360°. Therefore, we can set up a proportion to find the ratio between the central angle (90°) and the total circle measurement.

[tex]\frac{90}{360}[/tex]

Third Step: Equal out the two proportions and solve for the missing arc length

Now that we have our base proportion ([tex]\frac{90}{360}[/tex]), we can turn 60π into a proportion as well, leaving 60π as the denominator so we can solve for the arc length.

[tex]\frac{x}{60 \pi} = \frac{90}{360}[/tex]

We can now solve for x by cross multiplying.

  • [tex]\frac{90}{360} = \frac{1}{4}[/tex]
  • [tex]\frac{x}{60\pi} = \frac{1}{4}[/tex]
  • [tex]x = \frac{60\pi \cdot 1}{4}[/tex]
  • [tex]x = \frac{60\pi}{4}[/tex]
  • [tex]x = 15\pi \approx47.1[/tex]  

Hope this helped!