leslean
Answered

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Solve x2 + 6x = -6. If exact roots cannot be found, state the consecutive
integers between which the roots are located.

Sagot :

Dilshat

x²+6x＝-6 ‖+6

x²+6x+6＝0

x1＝-(6/2)+√((6/2)²-6)＝ -3+√(3) or ≈ -1.267

x2＝-(6/2)+√((6/2)²-6)＝ -3-√(3) or ≈ -4.732

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